/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 67 Breast-feeding mothers secrete c... [FREE SOLUTION] | ÷ÈÓ°Ö±²¥

÷ÈÓ°Ö±²¥

Breast-feeding mothers secrete calcium into their milk. Some of the calcium may come from their bones, so mothers may lose bone mineral. Researchers measured the percent change in bone mineral content (BMC) of the spines of 47randomly selected mothers during three months of breastfeeding. The mean change in BMC was -3.587%and the standard deviation was 2.506%.

(a) Construct and interpret a 99%confidence interval to estimate the mean percent change in BMC in the population.

(b) Based on your interval from (a), do these data give good evidence that on average nursing mothers lose bone mineral? Explain.

Short Answer

Expert verified

(a) We are 99%confident that the true population mean is between -4.5754%and -2.5986%.

(b) Yes, the data give good evidence that on average nursing mothers lose bone mineral.

Step by step solution

01

Part (a) Step 1: Given Information 

Given

x¯=-3.587

s=2.506

02

Part (a) Step 2: Explanation

Determine the t-value by looking in the row starting with degrees of freedom df=n-1=47-1=46>40and in the row with c=99%in table B:

t*=2.704

The margin of error is then:

localid="1650086388315" E=t*·sn=2.704×2.50647≈0.9884

Then the confidence interval becomes:

localid="1650086498431" -4.5754=-3.587-0.9884=x¯-E<μ<x¯+E=-3.587+0.9884=-2.5986

We are 99%confident that the true population mean is between -4.5754%and -2.5986%.

03

Part (b) Step 1: Given Information 

Given

x¯=-3.587

s=2.506

04

Part (b) Step 2: Explanation 

Confidence interval found in part (a):

-4.5754<μ<-2.5986

Since the confidence interval does not contain 0and lies completely below 0, the data gives good evidence that on average nursing mothers lose bone mineral.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with ÷ÈÓ°Ö±²¥!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Exercises 53 and 54 refer to the following setting. The table below displays the number of accidents at a factory during each hour of a 24-hour shift (1  1 a.m).

53. Accidents happen (1.2, 3.1)
(a) Construct a plot that displays the distribution of the number of accidents effectively.
(b) Construct a plot that shows the relationship between the number of accidents and the time when they occurred.
(c) Describe something that the plot in part (a) tells you about the data that the plot in part (b) does not.
(d) Describe something that the plot in part (b) tells you about the data that the plot in part (a) does not.

I collect an SRS of size n from a population and compute a 95%confidence interval for the population proportion. Which of the following would produce a new confidence interval with larger width (larger margin of error) based on these same data?

(a) Use a larger confidence level.

(b) Use a smaller confidence level.

(c) Increase the sample size.

(d) Use the same confidence level, but compute the interval n times. Approximately5% of these intervals will be larger.

(e) Nothing can guarantee absolutely that you will get a larger interval. One can only say that the chance of obtaining a larger interval is 0.05.

You have an SRS of 23 observations from a Normally distributed population. What critical value would you use to obtain a 98% confidence interval for the mean M of the population if S is unknown?

(a) 2.508

(b) 2.500

(c) 2.326

(d) 2.183

(e) 2.177

2K10 begins In January 2010, a Gallup Poll asked a random sample of adults, "In general, are you satisfied or dissatisfied with the way things are going in the United States at this time?" In all, 256said that they were sitisfied and the remaining 769said they were not. Construct and interpret a90%confidence interval for the proportion of adults who are satisfied with how things are going. Follow the four-step process.

Running red lights A random digit dialing telephone survey of880drivers asked, "Recalling the last ten traffic lights you drove through, how many of them were red when you entered the intersections?" Of the 880respondents, 171admitted that at least one light had been red.15

(a) Construct and interpret a95%confidence interval for the population proportion.

(b) Nonresponse is a practical problem for this survey-only 21.6%of calls that reached a live person were completed. Another practical problem is that people may not give truthful answers. What is the likely direction of the bias: do you think more or fewer than 171of the 880respondents really ran a red light? Why? Are these sources of bias included in the margin of error?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.