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Show that when \({\rm{X}}\) and \({\rm{Y}}\) are independent, \({\rm{Cov(X,Y) = Corr(X,Y) = 0}}\).

Short Answer

Expert verified

\({\rm{X}}\) and \({\rm{Y}}\) are independent when \({\rm{Cov(X,Y) = 0}}\).

Step by step solution

01

Definition

Probability simply refers to the likelihood of something occurring. We may talk about the probabilities of particular outcomes鈥攈ow likely they are鈥攚hen we're unclear about the result of an event. Statistics is the study of occurrences guided by probability.

02

Showing X and Y independent

Proposition:

The following holds

\({\rm{Cov(X,Y) = E(XY) - E(X) \times E(Y)}}\)

The

correlation coefficient

of \({\rm{X}}\) and \({\rm{Y}}\) is

\({{\rm{\rho }}_{{\rm{X,Y}}}}{\rm{ = }}\frac{{{\rm{Cov(X,Y)}}}}{{{{\rm{\sigma }}_{\rm{X}}}{\rm{ \times }}{{\rm{\sigma }}_{\rm{Y}}}}}\)

Assume that \({\rm{X}}\) and \({\rm{Y}}\) are independent, the following holds from the proposition

\(\begin{aligned}{\rm{Cov(X,Y) = E(XY) - E(X) \times E(Y)}}\\{\rm{ = E(X)E(Y) - E(X)E(Y)}}\\{\rm{ = 0}}{\rm{.}}\end{aligned}\)

When\({\rm{Cov(X,Y) = 0}}\), then\({\rm{\rho = 0}}\), which is obvious.

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