/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q4E Let A聽be an聽n脳m聽matrix. Is t... [FREE SOLUTION] | 魅影直播

魅影直播

Let Abe annmmatrix. Is the formula(kerA)=im(AT)necessarily true? Explain.

Short Answer

Expert verified

Yes.

Step by step solution

01

Determine the property of orthogonal.

Consider anm matrix A.

Theorem: For any matrix B, imB=kerBT .

By the definition, imAT=kerATT.

As role="math" localid="1659498837555" ATT=Aand A=A, take both side in the equation imAT=kerATTas follows.

imAT=kerATTimAT=kerAimAT=kerAimAT=kerA

Hence, the statement is true

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 魅影直播!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the subspaceim(A) of 2 . Where A=[2436] . Find a basis of ker(AT) , and draw a sketch illustrating the formula(imAT)=ker(AT)in this case.

Using paper and pencil, find the QR factorization of the matrices in Exercises 15 through 28. Compare with Exercises 1 through 14.

15.[21-2]

To make a trend analysis of six evenly spaced data points, one can use orthogonal polynomials with respect to evaluation at the points \(t = - 5, - 3, - 1,\,\,1,\,\,3,{\rm{ and }}5\).

  1. Show that the first three orthogonal polynomials are

\({p_0}\left( t \right) = 1,\,\,\,\,\,\,{p_1}\left( t \right) = t,{\rm{ and }}{p_2}\left( t \right) = \frac{3}{8}{t^2} - \frac{{35}}{8}\)

(The polynomial \({p_2}\) has been scaled so that its values at the evaluation points are small integers.)

  1. Fit a quadratic trend function to the data \(\left( { - 5,1} \right),\left( { - 3,1} \right),\left( { - 1,4} \right),\left( {1,4} \right),\left( {3,6} \right),\left( {5,8} \right)\).

Find the least-squares line \(y = {\beta _0} + {\beta _1}x\) that best fits the data \(\left( { - 2,0} \right),\left( { - 1,0} \right),\left( {0,2} \right),\left( {1,4} \right),{\rm{ and }}\left( {2,4} \right)\), assuming that the first and last data points are less reliable. Weight them half as much as the three interior points.

Consider a consistent system Ax=b.

(a) Show that this system has a solution x0 in (kerA) .

(b) Show that the systemAx=b has only one solution in (kerA) .

(c) Ifx0 is the solution in (kerA) androle="math" localid="1660124695419" x1is another solution of the system Ax=b , show that||x0||<||x1|| . The vectorx0 is called the minimal solution of the linear system Ax=b .

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.