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If the Census did another survey, kept the error bound the same, and surveyed only 50 people instead of 200, what would happen to the level of confidence? Why?

Short Answer

Expert verified

The confidence level decreases.

Step by step solution

01

Given Information

Only 50people instead of200.

02

Explanation

A tighter confidence interval with a smaller margin of error will arise from a bigger sample size or lower variability. A wider confidence interval with a larger margin of error will arise from a smaller sample size or higher variability.

The level of confidence would decrease because decreasing nmakes the confidence interval wider

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Most popular questions from this chapter

A poll of 1,200 voters asked what the most significant issue was in the upcoming election. Sixty-five percent answered the economy. We are interested in the population proportion of voters who feel the economy is the most important.

Define the random variable X in words

A poll of 1,200 voters asked what the most significant issue was in the upcoming election. Sixty-five percent answered the economy. We are interested in the population proportion of voters who feel the economy is the most important.

Define the random variable P′ in words.

If the Census wants to increase its level of confidence and keep the error bound the same by taking another survey, what changes should it make?

Define the random variablesX andx{"x":[[179,180,181,183,186,189,193,196,198,200,202,204,205,207,208,210,211,212,213,214,214,215,215,215,215,215,215,214,212,211,209,207,206,204,203,201,199,198,197,195,194,193,192,191],[226,225,224,221,219,218,217,215,214,213,213,212,212,211,211,211,211,211,211,212,213,214,216,217,220,223,225,227,229,232,233,235,236,238,239,240,241,242,242,243],[164,165,168,176,181,187,192,197,202,205,207,212,215,216,218,219,220,221,222]],"y":[[101,100,100,99,97,96,96,96,96,96,96,97,98,100,100,102,104,105,107,108,109,111,112,113,115,117,119,121,123,124,125,127,127,128,128,129,129,129,129,129,129,129,128,128],[88,89,90,93,95,97,98,100,101,103,104,104,105,107,108,109,110,111,113,114,114,115,116,118,119,120,121,121,121,121,121,121,121,121,120,120,120,120,119,119],[84,84,83,81,80,78,77,77,76,76,75,75,74,73,73,73,72,72,72]],"t":[[0,334,339,357,374,390,408,424,440,457,473,490,506,523,540,557,574,590,606,623,640,657,675,689,706,724,740,756,774,789,806,823,840,857,873,890,907,923,940,957,974,990,1006,1023],[2075,2299,2306,2324,2340,2356,2373,2389,2406,2423,2443,2458,2473,2490,2508,2523,2551,2590,2606,2623,2640,2656,2674,2690,2707,2723,2740,2756,2772,2789,2806,2823,2840,2856,2873,2890,2907,2956,2973,2989],[4121,4332,4340,4356,4373,4389,4406,4423,4440,4456,4473,4489,4506,4523,4539,4557,4573,4598,4656]],"version":"2.0.0"} in words.

Suppose that the insurance companies did do a survey. They randomly surveyed 400drivers and found that 320claimed they always buckle up. We are interested in the population proportion of drivers who claim they always buckle up.

a. i. x = __________ ii. n = __________ iii. p′ = __________

b. Define the random variables Xand P', in words.

c. Which distribution should you use for this problem? Explain your choice.

d. Construct a 95%confidence interval for the population proportion who claim they always buckle up. i. State the confidence interval. ii. Sketch the graph. iii. Calculate the error bound.

e. If this survey were done by telephone, list three difficulties the companies might have in obtaining random results.

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