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Chapter 10: Q. 43 (page 598)

Use the following information to answer the next five exercises. Two metal alloys are being considered as material for ball bearings. The mean melting point of the two alloys is to be compared. 15 pieces of each metal are being tested. Both populations have normal distributions. The following table is the result. It is believed that Alloy Zeta has a different melting point.

What is the p-value?

Short Answer

Expert verified

The value of p isp=0.0062

Step by step solution

01

Given Information

The table is


Sample Mean Melting TemperaturesF0

Population Standard Deviation
Alloy Gamma80095
Alloy Zeta900105
02

Determine the  p-value

To find the p-value press STAT and鈫�鈫�.

Twice to select TESTS.

Select the 2 - sample T test and press ENTER as displayed,

03

Simplifying

Once all the sample entries are made press ENTER to obtain the results as,

The p-value is 0.0062.

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