魅影直播

A test statistic value of $z=1.00$ is obtained, and the claim to be tested is $p>0.3$.

a.

In correspondence with the given claim, the following hypotheses are set up:

Null Hypothesis: $p=0.3$

Alternative Hypothesis: $p>0.3$

Where p is the population proportion.

Since there is greater than sign in the alternative hypothesis, the test is right-tailed.

b.

The test statistic to test the given claim is the z-value.

The z-value is equal to 1.00.

Using the standard normal table, the corresponding right-tailed p-value for z-score equal to 1.00 is equal to:

$$\begin{gathered} P\left(z>1.00\right)=1-P\left(z<1.00\right) \\ =1-0.8413 \\ =0.1587 \end{gathered}$$

Thus, the p-value is equal to 0.1587.

To depict the p-value on the normal probability graph, follow the given steps:

• Plot a horizontal axis representing the z-score. Also label it as 鈥渮-score鈥�.
• Sketch a bell-shaped curve and draw a vertical dotted line corresponding to the value 鈥�0鈥� on the horizontal axis
• Mark the point 鈥�1鈥� on the horizontal axis and then shade the area to the right of the value 鈥�1鈥� with blue as shown in the figure.
• Label the shaded region as 鈥減-value = 0.1587鈥�.

The following plot shows the probability value (p-value) as the shaded area under the normal probability graph:

c.

If the p-value is less than the level of significance, the null hypothesis is rejected; otherwise, not.

Here, the level of significance is equal to 0.05, and the p-value is equal to 0.1587.

Since the p-value is greater than 0.05, so the decision is to fail to reject the null hypothesis.