/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q38 In Exercises 37鈥40, refer to t... [FREE SOLUTION] | 魅影直播

魅影直播

In Exercises 37鈥40, refer to the frequency distribution in the given exercise and find the standard deviation by using the formula below, where x represents the class midpoint, f represents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviations to these standard deviations obtained by using Formula 3-4 with the original list of data values: (Exercise 37) 11.5 years; (Exercise 38) 8.9 years; (Exercise 39) 59.5; (Exercise 40) 65.4.

Standard deviation for frequency distribution

s=nfx2-fx2nn-1

Age (yr) of Best Actor When Oscar Was Won

Frequency

20-29

1

30-39

28

40-49

36

50-59

15

60-69

6

70-79

1

Short Answer

Expert verified

The calculated value of the standard deviation is equal to 9.6 years.

The calculated value of the standard deviation is approximately the same as the given value.

Step by step solution

01

Given information

The data showed the frequencies of the best actors according to their ages when they won the Oscar. The ages are grouped into 7 class intervals.

02

Formula

The formula for calculating thestandard deviation of a frequency distribution is expressed as follows:

s=nfx2-fx2nn-1

Here, f denotes the frequencies;

x denotes the midpoints of the class intervals;

n denotes the total frequency.

03

Calculations

The table below shows the necessary calculations:

Age

(in years)

Midpoint (x)

Frequency (f)

fx

x2

fx2

20-29

24.5

1

24.5

600.25

600.25

30-39

34.5

28

966

1190.25

33327

40-49

44.5

36

1602

1980.25

71289

50-59

54.5

15

817.5

2970.25

44553.75

60-69

64.5

6

387

4160.25

24961.5

70-79

74.5

1

74.5

5550.25

5550.25



n=87

fx=3871.5


fx2=180281.75

The value of standard deviation is calculated as follows, using the values obtained above:

s=nfx2-fx2nn-1=87180281.75-3871.528787-1=9.6

Therefore, the computed standard deviation is equal to9.6 years.

04

Comparison of computed value to the actual value

The actual value of standard deviation is 8.9 years.

Thus, the standard deviation computed from the sample is 9.6 years, which isquite close to the actual value equal to 8.9 years.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 魅影直播!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercises 17鈥20, use the following cell phone airport data speeds (Mbps) from Sprint. Find the percentile corresponding to the given data speed.

0.2 0.3 0.3 0.3 0.3 0.3 0.3 0.4 0.4 0.4 0.5 0.5 0.5 0.5 0.5 0.6 0.6 0.7 0.8 1.0 1.1 1.1 1.2 1.2 1.6 1.6 2.1 2.1 2.3 2.4 2.5 2.7 2.7 2.7 3.2 3.4 3.6 3.8 4.0 4.0 5.0 5.6 8.2 9.6 10.6 13.0 14.1 15.1 15.2 30.4

2.4 Mbps

Chebyshev鈥檚Theorem Based on Data Set 3 鈥淏ody Temperatures鈥 in Appendix B, body temperatures of healthy adults have a bell-shaped distribution with a mean of 98.20掳F and a standard deviation of 0.62掳F (using the data from 12 AM on day 2). Using Chebyshev鈥檚 theorem, what do we know about the percentage of healthy adults with body temperatures that are within 2 standard deviations of the mean? What are the minimum and maximum body temperatures that are within 2 standard deviations of the mean??

In Exercises 13鈥16, use z scores to compare the given values.

Tallest and Shortest Men The tallest living man at the time of this writing is Sultan Kosen, who has a height of 251 cm. The shortest living man is Chandra Bahadur Dangi, who has a height of 54.6 cm. Heights of men have a mean of 174.12 cm and a standard deviation of 7.10 cm. Which of these two men has the height that is more extreme?

In Exercises 21鈥28, use the same list of Sprint airport data speeds (Mbps) given for Exercises 17鈥20. Find the indicated percentile or quartile.

P75

In Exercises 5鈥20, find the range, variance, and standard deviation for the given sample data. Include appropriate units (such as 鈥渕inutes鈥) in your results. (The same data were used in Section 3-1, where we found measures of center. Here we find measures of variation.) Then answer the given questions.

TV Prices Listed below are selling prices in dollars of TVs that are 60 inches or larger and rated as a 鈥渂est buy鈥 by Consumer Reports magazine. Are the measures of variation likely to be typical for all TVs that are 60 inches or larger?

1800 1500 1200 1500 1400 1600 1500 950 1600 1150 1500 1750

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.