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The mean MCAT score is equal to 25.2.

The standard deviation of MCAT scores is equal to 6.4.

Thez-scoreof observation gives the distance of the observation from the mean in terms of standard deviations. Its value is calculated using the expression stated below:

$z=\frac{x-\stackrel{炉}{x}}{s}$

When the value of the z-score is equal to or below -2, the corresponding observation is significantly low.

When the value of the z-score is equal to or above 2, the corresponding observation is significantly high.

To obtain the significantly low values, the following computations need to be done:

$$\begin{gathered} z猢�-2 \\ \frac{x-\stackrel{炉}{x}}{s}猢�-2 \\ \frac{x-25.2}{6.4}猢�-2 \\ x猢�12.4 \end{gathered}$$

Therefore, MCAT scores equal to or below 12.4 aresignificantly low.

To obtain the significantly high values, the following computations are done:

$$\begin{gathered} z猢�2 \\ \frac{x-\stackrel{炉}{x}}{s}猢�2 \\ \frac{x-25.2}{6.4}猢�2 \\ x猢�38.0 \end{gathered}$$

Therefore, MCAT scores equal to or above 38.0 are significantly high.